Now Connect database1 using host, username and password as given below
$db1 = mysql_connect(”host”,”user”,”pwd”)
mysql_select_db(’db1name’, $db1);
Fire a query on db1
$res1 = mysql_query(”query”,$db1);

Connect database2 using host, username and password and include fourth parameter true as given below
$db2 = mysql_connect(”host”,”user”,”pwd”, true)
mysql_select_db(’db2name’, $db2);
Fire a query on db2
$res2 = mysql_query(”query”,$db2);

Now both link will remain live.If you will not use fourth parameter than setting of $db1 will be overwrite by $db2 so you can not use both objects without using this fourth parameter as true.Now after using fourth parameter you can use both database1 and database2 on same page.You can fetch data from first database and than insert that data in second database .

Today we will talk about left outer join .Not very common join but very effective join.
Suppose you have 2 tables. First “table1″ with 2 fields ‘id’ and ‘name.’ . Second “table2″ with 2 fields ‘id’ and ’salary’.In table1 “id” is primary key and in table2 field “id” is foreign key.

Suppose structure for 2 tables are like this:
Table1:                                                        Table2:
id       name                                                id       salary
————–                                                  —————–
1         aa                                                     2        2000
2          bb                                                   5         3000
3          cc                                                   NULL     NULL
4          cc
5          cc
6          cc
7          cc
8          cc
9          cc
10          cc

Now you want to fetch all records from table1 where id in table1 is not equal to id from table2 means we have to fetch records from both table1 where table1.id!=table2.id. One important thing about table2 that there may be null in id column.
Lot of programmers will try to do this by their logic means they will not use joins but try to fetch records saperatly from both tables and then make array and then write a logic to remove duplicate entries from array and then again run a query to fetch records for ids exists in final array.This is my thinking , may be they use another logic.

This process will take time to write whole code , also this will take extra space in file and we have to write more queries to fetch records.
Now here our left outer join is very effective solution.Using left outer join only single query will fetch all the records according to our need.
Here is the query:
“select table1.* from table1 LEFT OUTER JOIN table2 ON table1.id = table2.id WHERE table2.id IS NULL”

This will give you result like this.
Table1:
id       name
————–
1         aa
3          cc
4          cc
6          cc
7          cc
8          cc
9          cc
10          cc

This will give me a list off all the records that are in table1 but don’t have an entry in table2.

Just use this join and it will save your time and space.

INSERT INTO tablename1 (field1,field2,….,fieldn) SELECT field1,field2,….,fieldn FROM tablename2 WHERE condition

For ex. CONCAT(’firstname’,’ lastname’);

This functoin will concate this two word and create a single word.

Uses:

SELECT concat(’firstname’,'  ‘, ‘lastname’) AS name FROM tablename .

you can concat many words as you want.In the example above we also concated a space between firstname and lastname to seprate them

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